Can you identify the ploidy of different structures? drag the terms on the left to the appropriate blanks on the right to complete the sentences. terms may be used once, more than once, or not at all.
Answers 2
The question is incomplete. The complete question is as follows:
Can you identify the ploidy of different structures?
Drag the terms on the left to the appropriate blanks on the right to complete the sentences. Terms may be used once, more than once, or not at all.
diploid
haploid
polyploid
The gametophyte generation is ___________.
The megaspore is __________.
The sporophyte generation is ___________.
The embryo is __________.
Answer:
- haploid.
- haploid.
- diploid
- diploid.
Explanation:
The ploidy level represents the number of sets of chromosome in the living cell. The humans somatic cells are diploid whereas germ cells are halpoid in nature.
The gemetophyte are haploid in nature and megaspore are the gametic cells and are haploid in nature. The sporophyte cells have two sets of chromosome and are diploid in nature. Embryo is formed after the fertilization and diploid in nature.
Thus, the answer is - haploid.
- haploid.
- diploid
- diploid.
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This is an incomplete question, here is a complete question.
Draw a Lewis structure for H₂O that obeys the octet rule if possible and answer the following questions based on your drawing.
For the central oxygen atom:
The number of lone pairs =
The number of single bonds =
The number of double bonds =
Answer : The Lewis structure for H₂O is shown below.
For the central oxygen atom:
The number of lone pairs = 4
The number of single bonds = 2
The number of double bonds = 0
Explanation :
Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.
In the Lewis-dot structure the valance electrons are shown by 'dot'.
The representation of valence electrons of an atom by dots around the symbol of an element is said to be the Lewis-dot symbol.
In the representation of Lewis-symbol, one electron dot must put on each side of the element symbol then paired the electrons.
The given molecule is, H_2O
As we know that hydrogen has '1' valence electrons and oxygen has '6' valence electrons.
Therefore, the total number of valence electrons in H_2O = 2(1) + 6 = 8
According to Lewis-dot structure, there are 4 number of bonding electrons and 4 number of non-bonding electrons.
For the central oxygen atom:
The number of lone pairs = 4
The number of single bonds = 2
The number of double bonds = 0
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