xcc of 5N HCL was diluted to 1 litre of normal solution calculate the value of x​

Answers 2

Answer:

200cc of 5N HCl were diluted

Explanation:n

Assuming the solution was diluted to prepare a 1N HCl solution:

The HCl was diluted from 5N to 1N, that is a dilution of:

5N / 1N = 5 times

As the total volume of the diluted solution is 1L = 1000mL = 1000cc the amount of the concentrated solution was:

1000cc / 5 =

200cc of 5N HCl were diluted

AI generated Answer

for the quick answer Quick Answer: 0.12M Explanation: We use the formula C1V1 = C2V2 to calculate the concentration of xcc. C1 is 5N, V1 is xcc, C2 is 1N and V2 is 1000mL. Rearranging the equation we get C1/C2 = V2/V1. Therefore, xcc = (1000mL)(5N)/1N = 5000mL. Therefore, the concentration of xcc is 0.12M.
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