Which of the following correctly provides the name of the element, the symbol for the ion, and the name of the ion?a) fluorine, F, fluoride ionb) sulfur, S, sulfurous ionc) copper, Cu, cuprous iond) zinc, Zn, zincate ion
Answers 3
Answer: Option (a) is the correct answer.
Explanation:
When a non-metal gains an electron then it acquires a negative charge and when a metal loses an electron then it acquires a positive charge.
According to the IUPAC nomenclature, when a non-metal gains an electron then a suffix "-ide" is added at the end of the name of the ion. Whereas generally when a metal loses an electron then no suffix is added to its name but there are some exceptions.
For example, fluorine is a non-metal and when it gains one electron then it forms F^{-} ion which is known as the fluoride ion. Similarly, sulfur on gaining two electrons form S^{2-} ion which is known as sulfide ion.
Copper on loosing one electron forms Cu^{+} ion and it is known as cuprous ion or copper(I) and not Cu.
Thus, we can conclude that out of the given options fluorine, F, fluoride ion correctly provides the name of the element, the symbol for the ion, and the name of the ion.
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The element with the correct symbol for the ion, and the name of the ion has been fluorine, \rm F^-, Fluoride. ion. The correct option is a.
The elements tend to attain the stable electronic configuration and acquire the noble gas configuration. The elements gain electrons and acquire a -ve charge while losing electrons attain a +ve charge onto the element.
The IUPAC nomenclature gives the addition '-ide' as a suffix to the metal losing electrons.
- The fluorine has been a halogen losing an electron, the symbol is \rm F^-, and symbolized as Fluoride.
- Sulfur has been a nonmetal. and loses 2 electrons. The symbol has been \rm S^2^-, and the name has been Sulfide.
- Copper has been a transition metal that loses one electron to form \rm Cu^+, and the ion has been cupric ion.
- Zinc ion loses electron and form \rm Zn^2^+, the ion has been zinc ion.
Thus, the element with the correct symbol for the ion, and the name of the ion has been fluorine, \rm F^-, Fluoride. ion. The correct option is a.
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