An entrepreneur who opens a franchise must A. Assume debts. B. Keep profits. C. Offer training. D. Select sites.

Answer:

Subjectivity

Explanation:

Because it is

Answer:

Unconventionality

subjetivity

Explanation:

One of the main features of romanticism is the use of unconventionality isntead of rationalism.Poets wanted to make a difference and write in ways in which their feelings were more exploited.The practice also brought with it the use of subjectivity as a tool for expressing one ´s own views and opinions.

Answer:

The character experiences a variety of human emotions.  

The character possesses a complex personality.

The character grows or develops over the course of a play.

Explanation:A round character is one which resembles a complex, real person. A round character is likely to have complex personality and motivations, and to display a variety of human emotions. Moreover, he might not always be predictable, and might even be contradictory.

Flat and round characters are the two types of characters that are drawn in the literary pieces. A round character is a character that grows and develops throughout the story.

The ideas that describe a round character are:

• The character experiences a variety of human emotions. 
• The character possesses a complex personality. 
• The character grows or develops over the course of a play.

The progression of the story moves along with the progression of the character also. The character undergoes many changes and this brings interest to the audience or the readers to feel the new changes respectively. In the drama 'Hamlet' written by William Shakespeare, the character of Hamlet is a round character. The nature and behavior of Hamlet changed with every new event in the drama.

well, the movie lasted 1:38   so.... and she finished it at 1:10pm.

1:10pm minus 1 hour?  12:10pm.

12:10 pm minus 10 and minus 28 minutes?   12:10 - 00:10 = 12:00pm, 12:00 - 00:28 minutes = 11:32am.

Answer: 11:32

Step-by-step explanation:

Answer:

0.10 M AlCl₃.

Explanation:

We can calculate the concentration of chloride ion [Cl⁻] in each salt:

• 0.10 M MgCl₂:

MgCl₂ is dissociated according to the reaction:

MgCl₂ → Mg²⁺ + 2Cl⁻,

Every 1 mol of MgCl₂ produces 2 mol of Cl⁻.

So, [Cl⁻] = (2)*(0.1 M) = 0.2 M.

• 0.10 M AlCl₃:

AlCl₃ is dissociated according to the reaction:

AlCl₃ → Al³⁺ + 3Cl⁻,

Every 1 mol of AlCl₃ produces 3 mol of Cl⁻.

So, [Cl⁻] = (3)*(0.1 M) = 0.3 M.

• 0.05 M CaCl₂:

CaCl₂ is dissociated according to the reaction:

CaCl₂ → Ca²⁺ + 2Cl⁻,

Every 1 mol of CaCl₂ produces 2 mol of Cl⁻.

So, [Cl⁻] = (2)*(0.05 M) = 0.1 M.

• 0.10 M LiCl:

LiCl is dissociated according to the reaction:

LiCl → Li⁺ + Cl⁻,

Every 1 mol of LiCl produces 1 mol of Cl⁻.

So, [Cl⁻] = (1)*(0.1 M) = 0.1 M.

So, the solution will have the highest concentration of chloride ions is AlCl₃.

From the given options, the solution of 0.10M AlCl₃ is the one that has the highest concentration of chloride ions. 

To know which of the given solutions has the highest concentration of chloride ions, we must evaluate each of them.

1) 0.10 M MgCl₂

We can see that in 1 mol of MgCl₂, we have 1 mol of Mg²⁺ and 2 moles of Cl⁻ ions, so if the initial concentration of MgCl₂ is 0.10 M we have:

[Cl^{-}] = \frac{2\: moles\: Cl^{-}}{1 \: mol\: MgCl_{2}}*\frac{0.10 \:mol\: MgCl_{2}}{1 L} = 0.20 M 

Hence, in this solution we have 0.20 M of chloride ions.

2) 0.10 M AlCl₃

In 1 mol of AlCl₃, we have 1 mol of Al³⁺ and 3 moles of Cl⁻, so the concentration of Cl⁻ is:

[Cl^{-}] = \frac{3\: moles\: Cl^{-}}{1 \: mol\: AlCl_{3}}*\frac{0.10 \:mol\: AlCl_{3}}{1 L} = 0.30 M 

Then, the concentration of chloride ions in this solution is 0.30 M.

3) 0.05 M CaCl₂

We can notice that in 1 mol of CaCl₂ we have 1 mol of Ca²⁺ and 2 moles of Cl⁻. The concentration of Cl⁻ is:

[Cl^{-}] = \frac{2\: moles\: Cl^{-}}{1 \: mol\: CaCl_{2}}*\frac{0.05 \:mol\: CaCl_{2}}{1 L} = 0.10M

So, the concentration of the Cl⁻ ions is 0.10 M.

4) 0.10 M LiCl

In this case, in 1 mol of LiCl we have 1 mol of Li⁺ and 1 mol of Cl⁻, so the concentration of the chloride ions is:

[Cl^{-}] = \frac{1\: moles\: Cl^{-}}{1 \: mol\: LiCl}*\frac{0.10 \:mol\: LiCl}{1 L} = 0.10 M

Hence, in this solution the concentration of the Cl⁻ ions is 0.10 M.

Therefore, the solution 0.10M AlCl₃ has the highest concentration of chloride ions.