a food worker prepares chicken salad with chicken that was cooked three days ago. How should the food worker label the chicken salad?

Answer:

The i component of F is 7963.2 x 10⁻¹⁹ N.

The j component of F is 4561.2 x 10⁻¹⁹ N.

The k component of F is -151.2 x 10⁻¹⁹ N.

Magnitude of force is 9178.05 x 10⁻¹⁹ N.

Magnitude of force in presence of electric field is 27483.91 x 10⁻¹⁹ N.

Explanation:

Lorentz Force is defined as the force experience by charge particle in presence of electric and magnetic field. It is given by :

F = q ( v x B + E )     .....(1)

Here F is force, v is velocity of particle , B is magnetic field and E is electric field all are in vector notation and q is charge of the particle.

In first case, given :

E = 0

q = 24 x 10⁻¹⁹ C

v = [(-3.68)i + (6.35)j + (-1.91)k] x 105 m/s

B = [(-3.05)i + (5.28)j + (-1.09)k] T

Force, F = q x (v x B )

Substitute the suitable values in the above equation.

F = 24\times10^{-19}\times \left[\begin{array}{ccc}i&j&k\\-3.68&6.35&-1.91\\-3.05&5.28&-1.09\end{array}\right]\times105

F = 24 x 10⁻¹⁹ x { [6.35 x (-1.09) - (-1.91) x (5.28)] i - [(-3.68) x (-1.09) - (-1.91) x (-3.05)] j + [(-3.68) x (5.28) - 6.35 x (-3.05) ] k } x 105

F = 24 x 10⁻¹⁹ x 105 x [(3.16)i + (1.81)j + (-0.06)k] N   ....(2)

The i component of F is 7963.2 x 10⁻¹⁹ N.

The j component of F is 4561.2 x 10⁻¹⁹ N.

The k component of F is -151.2 x 10⁻¹⁹ N.

Magnitude of force, F =\sqrt{(7963.2\times10^{-19}) ^{2} +(4561.2\times10^{-19}) ^{2} +(-151.2\times10^{-19}) ^{2} }

F = 9178.05 x 10⁻¹⁹ N

In this case , E is also present and is equal to [(5.94)i + (-3.97)j + (-5.55)k] x 105 N/C. From equation (1) and (2) ;

F = 24 x 10⁻¹⁹ x [(3.16)i + (1.81)j + (-0.06)k + (5.94)i + (-3.97)j + (-5.55)k] x 105

F = 24 x 10⁻¹⁹ x 105 x [(9.1)i + (-2.16)j + (-5.61)k]

Magnitude of force, F = 24\times10^{-19}\times105\times\sqrt{9.1^{2}+(-2.16^{2})+(-5.61^{2}) }

F = 27483.9 x 10⁻¹⁹ N

Complete Question:

You can model the population of a certain city between 1955-2000 by the radical function

P(x) = 55,000 sqrt x-1945

Using this model, in which year was the population of that city 275,000?

Answer:

In 1970 population of that city is 275,000

Solution:

Given that,

You can model the population of a certain city between 1955-2000 by the radical function :

P(x) = 55000\sqrt{x - 1945}

To find: year in which was the population of that city 275,000

Therefore,

x = ?

P(x) = 275000

Thus we get,

275000 = 55000\sqrt{x - 1945}\\\\Divide\ both\ sides\ by\ 55000\\\\\frac{275000}{55000} = \sqrt{x-1945}\\\\5 = \sqrt{x - 1945}\\\\Take\ square\ on\ both\ sides\\\\25 = x - 1945\\\\x = 1945 + 25\\\\x = 1970

Thus, in 1970 population of that city is 275,000

The answer is A. 1970.

Answer:

True

Explanation:

Recreational time is the time in which you do your recreation. Recreational activities are often done for enjoyment, amusement, or pleasure and are considered to be "fun". Which means it can come before or after school.

Hope I helped answer the question:)

Recreation encompasses all of the activities that people engage in to refresh their bodies and minds and make their leisure time more interesting and enjoyable. Walking, swimming, meditation, reading, playing games, and dancing are all examples of recreational activities.

True, recreational time can come before or after school.

What are the types of recreational activity?

•  Indoor activities are also included in the recreation program. Indoor recreation activities are carried out in the comfort of one's own home or, more specifically, indoors, and are intended to rejuvenate the mind and soul.
• Outdoor sports, such as the ones mentioned, also provide us with a way to exercise and are thus among the best forms of recreation. Nature walks, river rafting, cycling, camping, fishing, hiking, adventure parks, surfing, and sports are all examples of outdoor recreation sports.

Thus, we can conclude that the given statement is true.

Answer:

 λ = -47 nC / m  

Explanation:

The missing question is as follows:

" The potential difference between the surface of a 2.2 cm -diameter power line and a point 1.9 m distant is 3.8 kV. What is the magnitude of the line charge density on the power line? Express your answer using two significant figures.  "

Given:

- The Diameter of the power line D = 2.2 cm

- The distance between two ends of power line L = 1.9m

- The potential difference across two ends V = 3.8 KV

Find:

What is the magnitude of the line charge density on the power line?

Solution:

- The derivation of the line of charges for a length L oriented along any axis centered at origin and the potential difference between two ends is as follows:

                                      V = 2*k*λ*Ln( D / L )

Where,

k : Coulomb's Constant = 8.99*10^9

 λ : The line charge density

- Re-arrange and solve for λ:

                                     λ = V / 2*k*Ln( D / L )

Plug in the values:

                                    λ = 3800 / 2*8.99*10^9*Ln( 2.2 / 190 )

                                    λ = -4.74022*10^-8 C / m

                                   λ = -47 nC / m