Brianna is feeling overwhelmed by the amount of digital information she receives each day. She is having a hard time determining what information is factual and reliable. Brianna may benefit from developing her skills in the information literacy area of: Group of answer choices Attention Critical consumption Collaboration Network awareness
Answers 2
Information literacy defines the ability to indentify, gather and make good use of available information in to solve problems and increase productivity. The problem of knowing the kind of information to digest is improved through the knowledge of critical consumption.
The size and amount of available information is so enormous, however, a sizeable amount of these information are not reliable and usually misleading.
With good critical consumption skill, an individual will be able to discern between reliable and unreliable information and by identifying sources and patterns in the gathered information.
Therefore, Brianna needs to develop her critical consumption skill.
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When the system is in equilibrium, the sum of the moment about a point is
zero.
Force \ shown \ by \ the \ scale \ under \ the \ right \ pillar \ is \ F = \dfrac{(m_B - 2 \cdot m_D) \cdot g}{2}
Reasons:
Length of the beam = l
Mass of the beam = m_B
Location \ of \ the \ two \ pillars = \dfrac{l}{3} \ from \ either \ end
Mass of the duck = m_D
Required:
Force shown by the scale under the right pillar.
Solution:
The location of the duck = On the left end of the beam
When the system is in equilibrium, we have; ∑M = 0
Taking moment about the left pillar, we get;
Clockwise moment = m_D \times g \times \dfrac{l}{3} + F \times \dfrac{l}{3}
Anticlockwise moment = m_B \times g \times \dfrac{l}{6}
At equilibrium, clockwise moment = Anticlockwise moment
Therefore;
m_D \times g \times \dfrac{l}{3} + F \times \dfrac{l}{3} = m_B \times g \times \dfrac{l}{6}
F \times \dfrac{l}{3} = m_B \times g \times \dfrac{l}{6} - m_D \times g \times \dfrac{l}{3}
F = \dfrac{m_B \times g \times \dfrac{l}{6} - m_D \times g \times \dfrac{l}{3}}{\dfrac{l}{3} } = \dfrac{(m_B - 2 \cdot m_D) \cdot g}{2}
Force \ shown \ by \ the \ scale \ under \ the \ right \ pillar, \ F = \dfrac{(m_B - 2 \cdot m_D) \cdot g}{2}
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