Which of the following is true about farmworkers in the system of share-tenancy? A.Farmers planted seed and used supplies bought by the landowners. B.Farmers paid cash rent to the landowners. C.Farmers had more control over their crops than with sharecropping. D.Farmers did not choose the crops they planted.

Answer:

C) you have the right to talk to the inspector privately

Explanation:

The idea with this rule is that employees will feel more free to raise potential safety concerns if they can do it in private.

Answer:

You have the right to talk to the inspector privately.

I took the test and got it right.

Answer:

The solutions for your four question problem are:

a) t = D^-1(x) =  (1/57)*x -(13/57)

b) t = D^-1(x) =  1 h

c) D^-1(x) represents time.

d) The number of hours of driving needed for Sarah to be x km from Tempe. (option (c))

Step-by-step explanation:

a) Determine a formula in terms of x for: t = D^-1(x)

The distance in km from Tempe after t hours of driving is given by

x = D(t) = 13 + 57t.

We just need to find the value  t function of x

x = 13 + 57*t

x -13 =  57*t

57*t  = x -13

t = (1/57)*x -(13/57)

We can see the plots of both equation in the picture below.

b) Compute D^-1(70)

Once we find the expression for D^-1(x)

We substitute for x = 70 km

t = D^-1(x) =  (1/57)*x -(13/57)

t = D^-1(x) =  (1/57)*(70) -(13/57)

t = D^-1(x) =  (70/57) -(13/57)

t = D^-1(x) =  (1.228) -(0.228)

t = D^-1(x) = 1 h

c) In the expression D^-1(x) :  what quantity (distance or time) does the x represent?  what quantity (distance or time) does the entire D^-1(x) represent?

x represents Distance in both equations (D(t), and D^-1(x))

t represents Time in both equations (D(t), and D^-1(x))

Since t = D^-1(x),

D^-1(x) represents time.

d) Which of the following statements best describes D^-1(x)?

The number of hours of driving needed for Sarah to be x km from Tempe.

Since, t = D^-1(x), and t represents the amount of time elapsed since Sarah, parted from Tempe, the correct answer is option (c)

The expression for D^-1(x) can be found in the previous answers

t = D^-1(x) =  (1/57)*x -(13/57)

The input is x (distance) and the output is t (time)

A) See ray diagram in attachment (-6.0 cm)

By looking at the ray diagram, we see that the image is located approximately at a distance of 6-7 cm from the lens. This can be confirmed by using the lens equation:

\frac{1}{q}=\frac{1}{f}-\frac{1}{p}

where

q is the distance of the image from the lens

f = -10 cm is the focal length (negative for a diverging lens)

p = 15 cm is the distance of the object from the lens

Solving for q,

\frac{1}{q}=\frac{1}{-10 cm}-\frac{1}{15 cm}=-0.167 cm^{-1}

q=\frac{1}{-0.167 cm^{-1}}=-6.0 cm

B) The image is upright

As we see from the ray diagram, the image is upright. This is also confirmed by the magnification equation:

h_i = - h_o \frac{q}{p}

where h_i, h_o are the size of the image and of the object, respectively.

Since q < 0 and p > o, we have that h_i >0, which means that the image is upright.

C) The image is virtual

As we see from the ray diagram, the image is on the same side of the object with respect to the lens: so, it is virtual.

This is also confirmed by the sign of q in the lens equation: since q < 0, it means that the image is virtual

The image distance from the lens is 6 cm.

The image formed by the diverging lens is upright and virtual.

Image distance

The image distance is calculated by using the following lens formula;

\frac{1}{v} = \frac{1}{f} - \frac{1}{u}

where;

• v is the image distance
• f is the focal length
• u is the object distance

\frac{1}{v} = \frac{-1}{10} - \frac{1}{15} \\\\\frac{1}{v} = \frac{-15 - 10}{150} \\\\\frac{1}{v} = \frac{-25}{150} \\\\v = -6 \ cm

The basic properties of image formed by a diverging lens

• Image is reduce
• Image is upright
• Image is virtual.

Answer:

a. short grasses and cacti

Explanation:

The semi-arid and arid areas in the western part of the United States are harsh environments, and only specialized plants for these conditions can survive. The climate is hot and dry, the precipitation very low, and the soil is poor. The plants that survive in these places have adapted well to survive with very little water, to manage to extract water from the air, to preserve it, and being able to sustain very high temperatures. The short grasses are the dominant plants int he semi arid regions. They do not require rich soil, nor lot of water, so they manage to survive on the bear minimum that is available. The trademark plants of the arid areas are the cacti. The cacti are able to store large amounts of water in them, have very long roots, are able to extract water from the air through their needles, and also have skin that doesn't allow any water to come out of it.

Answer:

The answer is A

Explanation: