The function of the ossicles in the middle ear is to transmit the vibrations of the tympanic membrane caused by sound waves propagated in air to the fluid-filled cochlea. In doing so, the ossicles change the nature of the vibrations. The ear tries to conserve the energy in the wave I, where v is the wave speed, cramster-equation-2010731130406341613664 is the density of the medium, cramster-equation-2010731131286341613668 is the frequency of the wave and A is the amplitude of the wave. Calculate the magnitude of the change in A that occurs. The density of air and water is 1.3x10–3g/cm3 and 1.0g/cm3, respectively, and the velocity of sound is 331 m/s in air and 1410 m/s in water. The frequency of the wave remains constant as the wave propagates. (Hint: Begin with to find .)

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Answer: The magnitude of the change in A is 8.55 dB. Explanation: We can use the conservation of energy equation to calculate the magnitude of the change in amplitude: I = I0*(v/v0)^2 * (rho/rho0) Where I0 is the initial intensity, v0 is the initial speed of sound, and rho0 is the initial density of the medium. We can rearrange this equation to solve for the change in amplitude: A2/A1 = (v0/v)^2 * (rho/rho0) For this problem, we have an initial speed of sound in air (331 m/s) and an initial density of 1.3 x 10-3 g/cm3, and a final speed of sound in water (1410 m/s) and a final density of 1.0 kg/m3. Plugging these values into the equation above gives us: A2/A1 = (331/1410)^2 * (1.0/1.3 x 10^-3) = 81.82 We can then take the logarithm of this value to get the magnitude of the change in amplitude in decibels (dB): log (81.82) = 8.55 dB Therefore, the magnitude of the change in A is 8.55 dB.

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Twelve students tried out for the cheerleading squad. Six students were selected. What is the ratio of the students selected to those trying out​

Answer:

1 : 2

Step-by-step explanation:

Twelve in total tried out for the cheering squad. The students selected were only 6 so the ratio would be 6 : 12 is shortened to 1 : 2.

1:2 12 students tried out. 6 made it, that is equal to 50%. That means for every one person selected, 2 tried out. Hope this helps
This is your code. >>> A = [21, 'dog', 'red'] >>> B = [35, 'cat', 'blue'] >>> C = [12, 'fish', 'green'] >>> E = [A, B, C] What is the value of E[1][2]? cat gree fish blue

Quick answer: The value of E[1][2] is 'blue'.

Explanation: In the given code, the variable E is assigned a list that contains three sublists: A, B, and C. Each sublist represents a collection of values. To access a specific value within the nested lists, we use indexing.

E[1] refers to the second sublist in E, which is [35, 'cat', 'blue']. To access the value at index 2 within this sublist, we use E[1][2]. The value at index 2 in the sublist [35, 'cat', 'blue'] is 'blue'.

Therefore, the value of E[1][2] is 'blue'.

4. The unit expressed the importance of remembering the mantra: Show, don't tell. Compose a sentence or two which implies the following settings without explicitly stating what the setting is. Cold, winter night Noisy restaurant ASAP 30 points

Answer:

Explanation:

I put on my winter coat and grab my keys. I get into the car and the engine rumbles on. The frost on my windsheald makes the road a bit blurry, but it will have to do. I park downtown, and walk into the restaurant. The floor rumbles from the music.

8.3.5: Max In List Write the function max_int_in_list that takes a list of ints and returns the biggest int in the list. You can assume that the list has at least one int in it. A call to this function would look like: my_list = [5, 2, -5, 10, 23, -21] biggest_int = max_int_in_list(my_list) # biggest_int is now 23 Do not use the built-in function max in your program! Hint: The highest number in the list might be negative! Make sure your function correctly handles that case.

Answer:

here!!

Explanation:

# Write code here...

def max_int_in_list(my_list):

   highest = my_list[4]

   

   for num in my_list:

       if num > highest:

           highest = num

       return highest

my_list = [5, 2, -5, 10, 23, -21]

biggest_int = max_int_in_list(my_list)

print biggest_int

A version of the required program written in python 3 is given below.

my_list = [5, 2, -5, 10, 23, -21]

def max_int_in_list(my_list):

#iniate the function named max_int_in_list which takes in a list argument

maximum = my_list[0]

#set the first value in the list as maximum

for num in my_list:

#iterate through every value in the list

if num > maximum:

#Check if any of the iterated values in the list is greater than the set maximum value

maximum = num

#if so set the Number as the new maximum value

return maximum

#return the maximum value

print(max_int_in_list(my_list))

A SCREENSHOT of the program output is attached.

answer img

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