S m On a frictionless toy race track, a 0.035 kg toy car moving right at 0.30 collides with another 0.040 kg toy m car moving left at 0.20 After the collision, the 0.035 kg car moves left at 0.20 S m S What is the final speed of the 0.040 kg toy car?

Answers 2

Answer: 0.24 m/s

Explanation:

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AI generated Answer

Q Quick Answer: 0.10 m/s Explanation: Conservation of momentum states that the total linear momentum of an isolated system will remain constant. Therefore, the final momentum of the two cars must be the same as the initial momentum. The initial momentum of the 0.035 kg car is 0.30*0.035 = 0.0105 kg·m/s. The initial momentum of the 0.040 kg car is 0.20*0.040 = 0.0080 kg·m/s. Therefore, the final momentum of the 0.040 kg car must be 0.0105 - 0.0080 = 0.0025 kg·m/s. Since the mass of the 0.040 kg car is known, the final speed can be calculated by dividing the final momentum by the mass, which is 0.0025/0.040 = 0.10 m/s.
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