Cuales son las sinalefas de este poema? Una rosa blanca Cultivo una rosa blanca, en julio como en enero, para el amigo sincero que me da su mano franca. Y para el cruel que me arranca el corazón con que vivo, cardo ni ortiga cultivo: cultivo una rosa blanca.
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Subject:
Spanish -
Author:
siennaaok7 -
Created:
1 year ago
Answers 3
Answer:
Las sinalefas se han destacado con un subrayado:
Cultivo una rosa blanca,
en julio como en enero,
para el amigo sincero
que me da su mano franca.
Y para el cruel que me arranca
el corazón con que vivo,
cardo ni ortiga cultivo:
cultivo una rosa blanca.
Explanation:
La sinalefa es una figura poética de transformación que consiste en juntar dos sílabas, la primera debe termina con una vocal y la segunda debe cpmenzar con una vocal. Ambas sílabas pasan a ser consideradas como si fueran una sola sílaba. El uso del recurso de la sinalefa permite que el poema "Cultivo una rosa blanca", de José Martí, tenga como métrica en cada verso ocho sílabas, o sea que a pesar de que las sílabas son más, los versos se convierten en octosílabos.
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Author:
tessa53
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Rate an answer:
10
El Sinalefas nos permite mencionar la unión que se forma cuando una palabra termina en vocal y la siguiente también comienza en vocal.
The Sinalefas allows us to mention the union that is formed when one word ends in a vowel and the following also begins in a vowel
Sinalefas de este poemaCultivo una rosa blanca,
en julio como en enero,
para el amigo sincero
que me da su mano franca.
Y para el cruel que me arranca
el corazón con que vivo,
cardo ni ortiga cultivo:
cultivo una rosa blanca.
En esta pregunta, podemos identificar las Sinalefas
In this question, we can identify the Sinalefas
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Author:
christiankbmm
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Other related questions that may help you
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Author:
carmenovog
Answer:
A) attached below
B) I₁ = 18.1 A , I₂ = 69.39 A
C) V( magnitude) = 454.5 ∠ 5.04° V , Voltage regulation = ≈ -1.2%
Explanation:
A) Schematic diagram attached below
attached below
B) magnitude of primary and secondary winding currents
I₂ ( secondary current ) = P / √3 * VL * cos∅ ---------- ( 1 )
VL = Line voltage = 208
cos∅ ( power factor ) = 0.8
P = 20 * 10^3 watts
insert values into equation 1
I₂ = 69.39 A
I₁ ( primary current ) = I₂V2 / V1
I₁ = ( 69.39 * 120 ) / 460 = 18.1 A
C ) Calculate the Primary voltage magnitude and the Voltage regulation
V(magnitude ) = Vp + ( I₁ ∠∅ ) Req ( 1 + j2 = 2.24 ∠63.43° )
= 460 + ( 18.1 * cos^-1 (0.8) ) ( 1 + j2 )
= 460 + 40.544 ∠ 100.3°
∴ V( magnitude) = 454.5 ∠ 5.04° V
Voltage regulation
= ((Vmag - V1) / V1 )) * 100
= (( 454.5 - 460 / 460 )) * 100
= -1.195 % ≈ -1.2%
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