write an ionic half equation for the formation of hydrogen during this electrolysis
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Subject:
Chemistry -
Author:
presleymeza -
Created:
1 year ago
Answers 3
Answer:
A half-equation shows you what happens at one of the electrodes during electrolysis. Electrons are shown as e-. A half-equation is balanced by adding, or taking away, a number of electrons equal to the total number of charges on the ions in the equation.
When positive metal ions (cations) arrive at the negative electrode (the cathode), they gain electrons to form neutral metal atoms. This is called reduction. For example:
Pb2+ + 2e- → Pb
When negative non-metal ions (anions) arrive at the positive electrode (the anode), they lose electrons to form neutral atoms or molecules. This is called oxidation. For example:
2Br- → Br2 + 2e-
Writing half equations
Cations go to the cathode. They need to gain enough electrons to make them neutral. So an Al3+ ion needs to gain three electrons:
Al3+ + 3e- → Al
Half-equations for non-metal anions are more difficult to balance. For example, chloride ions make chlorine gas. Most non-metal elements formed in electrolysis are diatomic molecules (eg Cl2). For example:
Cl- → Cl2
Add in two electrons to balance the charge so that both sides have the same charge. The two electrons need to go on the right-hand side, so that both sides have an overall charge of -2. For example:
2Cl- → Cl2 + 2e-
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Author:
jamiereid
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Although your question lacks some information a general answer is provided
The ionic half equation = 2H^{+} (aq) + 2e^{-} ----> H_{2} (g)
The formation of hydrogen takes place at the negative electrode in a cell and the ionic half reaction that shows the formation of the hydrogen gas at the electrode is written as :
2H^{+} (aq) + 2e^{-} ----> H_{2} (g)
Ionic half equation is the representation of the chemical activity ( reaction ) occurring at one of the electrodes of a cell. to balance a half reaction we add or remove electrons equal to charges on the ions.
Hence the Ionic half equation for the formation of hydrogen during electrolysis is written as ; 2H^{+} (aq) + 2e^{-} ----> H_{2} (g)
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