How many moles are in 123.0 grams of KClO4? (3 points) 0.2354 mol KClO4 0.6445 mol KClO4 0.7124 mol KClO4 0.8878 mol KClO4
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Subject:
Chemistry -
Author:
dontemcfarland -
Created:
1 year ago
Answers 3
Answer:
0.8878 mol KClO4
Explanation:
Molar mass of KClO4 = 39.0983 + 35.453 + ( 15.9994 x 4 ) = 39.0983 + 35.453 + 63.9976 = 138.5489g/mol
but,
number of moles = mass in grams / molar mass where mass in grams = 123g, molar mass = 138.5489g/mol
number of moles = 123g / 138.5489g/mol = 0.8878mol
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Author:
keyla
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Rate an answer:
19
Therefore the number of moles present in 123 g of KClO_4 is 0.888 moles.
Given,
The weight of the KClO_4 is 123. grams
molecular weight of KClO_4 is 39+35.5+16\times4=138.5 g
138.5 g of KclO_4 is equal to one mole
Gram molecular wt. of a substance is equal to one mole
No. of moles = \frac{Wt}{GMW}
123 g of KClO_4 is equal to \frac{123}{138.5}=0.888 moles
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Author:
keegan199
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Rate an answer:
2
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