A beam of particles, each with a charge of 24.0 x 10-19 C, moves at [ (-3.68)i + (6.35)j + (-1.91)k ] x 105 m/s through a uniform magnetic field of [ (-3.05)i + (5.28)j + (-1.09)k ] T. Let F represent the force vector on each particle. What is the i component of F? (include units with answer) What is the j component of F? (include units with answer) What is the k component of F? (include units with answer) What is the magnitude of F? (include units with answer) A uniform electric field of [ (5.94)i + (-3.97)j + (-5.55)k ] x 105 N/C is added to the system. What is the new magnitude of F? (include units with answer)

Explanation:

Join G⭕new in how many years will 24000 amount to 27783 at 5% per annum compounded annually?

Answer: The ratio of \frac{[Sn^{2+}_{(diluted)}}{[Sn^{2+}_{(concentrated)}]}  in the cell is 4.07\times 10^{-4}

Explanation:

The half reactions for the cell is:  

Oxidation half reaction (anode):  Sn(s)\rightarrow Sn^{2+}+2e^-

Reduction half reaction (cathode):  Sn^{2+}+2e^-\rightarrow Sn(s)

In this case, the cathode and anode both are same. So, E^o_{cell} will be equal to zero.

To calculate cell potential of the cell, we use the equation given by Nernst, which is:

E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Sn^{2+}_{(diluted)}}{[Sn^{2+}_{(concentrated)}]}

where,

n = number of electrons in oxidation-reduction reaction = 2

E_{cell} = 0.10 V

\frac{[Sn^{2+}_{(diluted)}}{[Sn^{2+}_{(concentrated)}]}  = ?

Putting values in above equation, we get:

0.10=0-\frac{0.0592}{2}\log \frac{[Sn^{2+}_{(diluted)}}{[Sn^{2+}_{(concentrated)}]}

\frac{[Sn^{2+}_{(diluted)}}{[Sn^{2+}_{(concentrated)}]}=4.016\times 10^{-4}

Hence, the ratio of \frac{[Sn^{2+}_{(diluted)}}{[Sn^{2+}_{(concentrated)}]}  in the cell is 4.016\times 10^{-4}

The ratio of the Sn2+ concentrations in the two half-cells is 0.00042.

The cell reaction is; Sn(s) ------> Sn^2+(aq) + 2e

Using the Nernst equation;

Ecell = E°cell - 0.0592/n log Q

Ecell = 0.10 V

n = 2

Q = ?

E°cell = 0.00 V

0.10 V = 0.00 V - 0.0592/2 log Q

-(0.10 V × 2/0.0592) = log Q

-3.378 = log Q

Q = 0.00042

Complete Question:

You can model the population of a certain city between 1955-2000 by the radical function

P(x) = 55,000 sqrt x-1945

Using this model, in which year was the population of that city 275,000?

Answer:

In 1970 population of that city is 275,000

Solution:

Given that,

You can model the population of a certain city between 1955-2000 by the radical function :

P(x) = 55000\sqrt{x - 1945}

To find: year in which was the population of that city 275,000

Therefore,

x = ?

P(x) = 275000

Thus we get,

275000 = 55000\sqrt{x - 1945}\\\\Divide\ both\ sides\ by\ 55000\\\\\frac{275000}{55000} = \sqrt{x-1945}\\\\5 = \sqrt{x - 1945}\\\\Take\ square\ on\ both\ sides\\\\25 = x - 1945\\\\x = 1945 + 25\\\\x = 1970

Thus, in 1970 population of that city is 275,000

The answer is A. 1970.

Answer:

as being 3 days old

Explanation:

In this specific scenario, the food worker should label the food as being 3 days old. This is because when working in the food industry, the food needs to be labeled with the date of the oldest cooked ingredient. In this case, it would be the chicken.

When foods are unfrozen or cooked, microorganisms begin growing on the foods surface and more enzyme activity begins to take place. This increases the rate at which the food ultimately spoils. Chicken for example is safe to eat, up to 4 days after it has been cooked according to the CDC.

Therefore, the food worker should label the food as being 3 days old to comply with the food industry regulations as well as make sure that the food does not pass its expiry timeframe and is sold. Which can cause someone to become sick.

How the food worker should label the chicken salad

The food worker should label the chicken salad 3 days ago

Labelling of food should be done according to how long the food has been prepared. This is to ensure that food cooked a long time ago is served first before serving food cooked recently.

When cooked food are kept for too long, germs grow on it which causes food poisoning or food wastage.