A researcher shows the same video of an automobile accident to two different groups of participants. Participants in group one are asked: "Did you see a broken headlight?" Participants in group two are asked: "Did you see the broken headlight?" The researcher finds that participants in group two are much more likely to recall having seen a broken headlight, even though there actually was no broken headlight in the video. The researcher is investigating the effects of which of the following on recall?

Answer: options 1 and 3

Explanation:

The function of a rheostat relates mainly:

- Limits the current in the circuit.

- it's used as a aid to adjusting the current in the circuit.

The purpose of the rheostat in this experiment is option 1 and option 3.

Information regarding the rheostat:

• It limits the current in the circuit.
• Also, it aids for adjusting the current in the circuit.
• So, the option 1 and option 3 should represent the purpose.
• Therefore, the option 2 and option 4 is wrong.

To develop this problem we will apply the concepts related to the conservation of momentum. For this purpose we will define that the initial moment must be preserved and be equal to the final moment. Since the system was at a stationary moment, the moment before the bullet is fired will be 0, while the moment after the bullet is fired will be equivalent to the sum of the products of the mass and the velocity of each object. , this is,

m_1u_1+m_2u_2 = m_1v_1+m_2v_2

Here,

m = mass of each object

u = Initial velocity of each object

v = Final velocity of each object

Our values are,

\text{Mass of hunter} ) m_1 = 75 kg = 75000 g

\text{Mass of bullet} = m_2 = 42 g

\text{Speed of bullet} = v_2 = 6200 m/s

\text{Recoil speed of hunter} =v_1 = ?

Applying our considerations we have that the above formula would become,

m_1v_1 + m_2v_2 = 0

Solving for speed 1,

v_1 = - \frac{m_2v_2}{m_1 }

v_1 = - \frac{42 * 620}{75000 }

v_1 = - 0.3472 m/s

Therefore  the recoil speed of the hunter is -0.3472m/s, said speed being opposite to the movement of the bullet.

The recoil speed of the hunter standing on the frictionless ice is 0.35m/s².

Given the data in the question;

• Mass of hunter; m_1 = 75kg
• Mass of bullet; m_2 = 42g = 0.042kg
• Velocity of bullet; v_2 = 620m/s

Recoil speed of the hunter; v_1 =\ ?

From the law of conservation of momentum:

MV = mv

Where m is mass and v is velocity

So

m_1v_1 = m_2v_2\\\\v_1 = \frac{m_2v_2}{m_1}

We substitute our given values into the equation

v_1 = \frac{ 0.042kg \ *\ 620m/s^2}{75kg} \\\\v_1 = \frac{26.04kg.m/s^2}{75kg} \\\\v_1 = 0.35m/s^2

Therefore, the recoil speed of the hunter standing on the frictionless ice is 0.35m/s².

Answer:

A) Differential equation for population growth in case of individual immigration is:

\frac{dP}{dt}=kP+r

B) Differential equation for population growth in case of individual emigration is:

\frac{dP}{dt}=kP-r

Step-by-step explanation:

Population growth rate  in the absence of immigration and emigration is given as:

\frac{dP}{dt}=kP--(1)

A) When individuals are allowed to immigrate:

Let r be the constant rate of individual immigration given that r >0.

Differential equation for population growth in this case is:

\frac{dP}{dt}=kP+r

B) In case of individual emigration:

Let r be the constant rate of individual emigration given that r >0.

Differential equation for population growth in this case is:

\frac{dP}{dt}=kP-r

Answer:

Enrique y yessica tenían

Tomas y Elena podían

los inmigrantes tuvieron miedo

los ciudadanos no pudieron